Go语言视频零基础入门到精通

小飞哥

SELECT * FROM(
SELECT TOP 30 * FROM (
SELECT TOP 40 * FROM A ORDER BY id ASC
) AS tempTableOne ORDER BY id DESC
) AS tempTableTwo
ORDER BY Eid ASC

2878qw

赞一个.

apekji

SQL code 取n到m行

1.
select top (n-m+1) * from tablename where id not in (select top n id from tablename order by id asc/*|desc*/)

2.
select top m * into 临时表(或表变量) from tablename order by columnname -- 将top m笔插入到临时表
set rowcount n   --只取n条结果
select * from 表变量 order by columnname desc

3.
select top n * from  
(select top m * from tablename order by columnname) a
order by columnname desc


4.如果tablename里没有其他identity列，那么：
先生成一个序列,存储在一临时表中.
select identity(int) id0,* into #temp from tablename

取n到m条的语句为：
select * from #temp where id0 > =n and id0  <= m

如果你在执行select identity(int) id0,* into #temp from tablename这条语句的时候报错,那是因为你的DB中间的select into/bulkcopy属性没有打开要先执行：
exec sp_dboption 你的DB名字,'select into/bulkcopy',true


5.如果表里有identity属性，那么简单：
select * from tablename where identity_col between n and m  

6.SQL2005开始.可以使用row_number() over()生成行号
;with cte as
(
select id0=row_number() over(order by id),* from tablename
)
select * from cte where id0 between n to m

yy1020

第一个改top 10

太阳城

结帖率：0.00%

卡卡的梦

SQL code SQL2005以上版本用 row_number

select *
from (select * ,row=row_number()over(order by ID asc) from A)t
where row between 31 and 40

2878qw

SQL code
select * from (select *,row_number() over(order by id) number from A) a where number>30 and number <40

8jnuj3

Assembly code select * from (select top 40 * from A) a left join (select top 30 * from A) b on a.xx=b.xx where b.xx is null

水中月

貌似有点问题哦

第31到40条应该是
SQL code selet top 10 * from(
select top 40 * from A order by id asc
)as t order by id desc


另外,楼主的说法也有点问题,如果不加排序,那"表中第31到40条记录"这句话是有点毛病的.....